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Re: Ask Alex @ MBA Apply

Africa1989 wrote:Good Afternoon, I had a question with regards to MBA admissions for “Under Represented Minorities”. The internet seems to be rife with stories about X URM candidate who got into...

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Re: If m

Bunuel wrote:debayan222 wrote:If m<0, which of the following must be true? A. –100 < m < 100 B. m ≤ –1 C. m ≤ 1 D. m^2 ≥ 1/4 E. –100 < m < 0 P.S: Bunuel/VeritasPrepKarishma- guys I would...

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Re: Tuck (Dartmouth): Class of 2016- Calling all applicants!

Looking to apply in the Early Action period too; From what I have read, I get really good vibes about the school.

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Re: For positive integers x and y, which of the following can

The question is asking "Which of these equations could equal a perfect square?" If you're familiar with number properties regarding perfect squares, you should be able to rule out everything except the...

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Re: INSEAD Waitlist - September 2013 Intake

ducceus wrote:Hello, Can someone be so kind, and post stat of nationality on MBA connect ? At the least, can you told me how many Vietnamese get accepted ? I dont know how relevant that number will be,...

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Re: INSEAD September 2013 - Calling All Applicants

Seyar78 wrote:Hello, Can someone post stat of french nationality on MBA connect ? Many thanks 36, lots of dual nationalities though.

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Re: INSEAD Waitlist - September 2013 Intake

TaipanRex wrote:ducceus wrote:Hello, Can someone be so kind, and post stat of nationality on MBA connect ? At the least, can you told me how many Vietnamese get accepted ? I dont know how relevant that...

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Re: Calling all Anderson(UCLA) FEMBA 2013 Applicants!

No idea.. I was interviewed and my status has changed to Submitted as well.. This wait is killing me.. Posted from my mobile device

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Re: The fewer restrictions there are on the advertising -MBeTrue

why is D not the answer. D. If more lawyers advertise lower prices for specific services, some lawyers who do not advertise will also charge less than they currently charge for those services. This...

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Re: Is |x-1| < 1?

Can someone explain to me how you arrive at 0<x≤2? I simplified (x-1)^2≤1 down to x(x-2)≤0 and I see that x≤2 but how do you get x<0? Thanks!

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Re: We are LIVE at AIGAC 2013 Conference! Follow us on Twitter!

A Great initiative & some very useful insights. +1 Rhyme

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Line M is tangent to a circle, which is centered on point

Line M is tangent to a circle, which is centered on point (3, 4). Does Line M run through point (6, 6)? (1) Line M runs through point (-8, 6) (2) Line M is tangent to the circle at point (3, 6) Thanks...

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Re: Which of the following numbers is not prime ?

Bunuel wrote:Don't get your solution... The property you are referring to is: any prime number p greater than 3 could be expressed as p=6n+1 or p=6n+5 (p=6n-1), where n is an integer >1. That's...

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Re: 700 Clubbers...add your name to the list!

Username: nick770 Score: 770 - 51Q/42V Date: Jun 2013 Best Prep Materials: OG 12/13 , Manhattan SC Guide , Manhattan Advanced GMAT Quant Strategy Guide , Power Score CR Bible , GMAT Prep ( free soft +...

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Re: C-Blast is a hearty blend of powerful vitamins, minerals, an

C-Blast is a hearty blend of powerful vitamins, minerals, and immunity-boosting micronutrients that promotes a healthy metabolism, soothes the stomach, comes packaged in a high-tech bottle, and gives...

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Re: We are LIVE at AIGAC 2013 Conference! Follow us on Twitter!

Very awesome Rhyme - Thank you for sharing!

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Re: In the figure above, triangle ABC is equilateral, and point

Is there any other way to solve this problem? I'm having trouble understanding the principles behind it. How did you know to use central angles? Thanks! pavan2185 wrote:Bunuel wrote:pavan2185...

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Re: INSEAD -January 2014 Intake - Calling All Applicants

I think we beat this horse to the dead already, but here is admission insights o.O http://www.youtube.com/watch?v=Jngcu8fdnWo

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Re: Just accepted at Tepper, but should I go?

Thanks for the replies guys. I just passed on the offer, and will be applying to another batch of schools for next year. Tepper is an extraordinary program, but I want to see what will happen next...

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Is P + Q > 1/P + 1/ Q?

Is P + Q > 1/P + 1/ Q? 1) P < Q < 1 2) PQ < 1

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