Bunuel wrote:
Each of 6 blue diagonals equal to 2*(side*\frac{\sqrt{3}}{2})=5\sqrt{3} (notice that in 30°, 60°, 90° triangle, where the sides are always in the ratio 1 : \sqrt{3}: 2, half of the blue diagonal is the leg opposite 60°, so it equals to side*\frac{\sqrt{3}}{2});
Bunuel: Can you please explain the above mentioned step in detail. How did you calculate the 90 degree angle or the small 30 degree angle ?
Thank you