ramgmat wrote:
Hi all,
I tried solving it using the formulas of matrices using the formula \frac{1}{2}[x1 (y2-y3) + x2( y3-y1) + x3(y1-y2)] and got the answer as 4. Took the values for x1, x2, x3 and y1, y2, y3 as the values of the three co-ordinates of the vertices.
Can you please tell me where am I making a mistake?
I tried solving it using the formulas of matrices using the formula \frac{1}{2}[x1 (y2-y3) + x2( y3-y1) + x3(y1-y2)] and got the answer as 4. Took the values for x1, x2, x3 and y1, y2, y3 as the values of the three co-ordinates of the vertices.
Can you please tell me where am I making a mistake?
May be you did some calculation mistake perhaps?
I applied the formula 1/2 * (5 (5-3) + 3 * (3-1) + 1 * (1-5))
=1/2 * (10+6-4)
=6
Hence, D
PS: Like my approach? Help me with some Kudos.
