fozzzy wrote:
If a regular hexagon is inscribed in a circle with a radius of 4, the area of the hexagon is
a) 12 root 3
b) 8 pi
c) 18 root 2
d) 24 root 3
e) 48
Image
https://s3.amazonaws.com/production.gro ... .13_pm.png
a) 12 root 3
b) 8 pi
c) 18 root 2
d) 24 root 3
e) 48
Image
https://s3.amazonaws.com/production.gro ... .13_pm.png
A regular hexagon is essentially composed of 6 equilateral trianlges...and the line joining the opposite vertices is the diameter of the circle in which the hexagon is inscribed...So the radius of the circle forms the side of the equilateral triangle...
Area is 6* (3^1/2)/4(a^2) where a = radius of the circle.
6*sq. rt3/4 * 4^2=24 root 3