Quantcast
Channel: GMAT Club Forum - latest posts
Viewing all articles
Browse latest Browse all 421237

Re: In the xy plane line m has the equation 4x + y = k. Line n

$
0
0
newC wrote:
In the xy plane line m has the equation 4x + y = k. Line n passes through the origin and is perpendicular to line m. If point p has the coordinates (r, r+1) and is on both line n and m what is the value of r?

A. -4/3
B. 1/4
C. -4
D. 3/4
E. 4/3

Can anybody help me with this problem?! I really have no idea how to attack this problem..
Thanks!!


You can approach by calculating slopes of both lines m and n.

As we know both m and n lines are perpendicular; slope m* slope n= -1

slope of m= -4 since 4x=y+k =>(Y=mx+c), where m is slope

now calculate slope of n. as we know line passes through origin (0,0) and (r, r+1)

slope = (y2-y1)/(x2-x1) => (r+1-0)/(r-0) => (r+1)/r

lines are perpendicular; thus we can multiply both slopes

(r+1)/r*-4=-1 gives r= -4/3

Hence Ans is A.

Hit Kudos if you like it... :-D

Viewing all articles
Browse latest Browse all 421237

Trending Articles



<script src="https://jsc.adskeeper.com/r/s/rssing.com.1596347.js" async> </script>