A 10 liter mixture of cranberry juice and water contains juice and water in the ratio of 3 : 2. 5 liters of the mixture are removed and replaced with pure juice and the operation is repeated once more. At the end of the two removals and replacements, what is the ratio of juice to water in the resulting mixture?
10 = 6Juice + 4 Water
When 5 litre is removed ,because the ratio is 3:2 , 3L Juice and 2L Water is removed and when 5L juice is added then the above equation becomes
10=8Juice + 2 Water
In the second go , the ratio now is 4:1 , when we take out 5L of the mixture , 4L of Juice and 1L of Water is taken out and when we add 5L of pure juice the above equation becomes
10 = (8-4+5)Juice + (2-1+0)Water
Which is 9:1 and hence E is the answer
10 = 6Juice + 4 Water
When 5 litre is removed ,because the ratio is 3:2 , 3L Juice and 2L Water is removed and when 5L juice is added then the above equation becomes
10=8Juice + 2 Water
In the second go , the ratio now is 4:1 , when we take out 5L of the mixture , 4L of Juice and 1L of Water is taken out and when we add 5L of pure juice the above equation becomes
10 = (8-4+5)Juice + (2-1+0)Water
Which is 9:1 and hence E is the answer