karjan07 wrote:
Bunuel,
When to use
1.\sqrt{x} = Mod(X) or
2. \sqrt{X} = X
Here u have used \sqrt{x} = Mod(X) while in the problem below:
If \sqrt{3-2x}= \sqrt{2x} +1 then 4x2 =
(A) 1
(B) 4
(C) 2 − 2x
(D) 4x − 2
(E) 6x − 1
you have used \sqrt{X} = X
Why so?
When to use
1.\sqrt{x} = Mod(X) or
2. \sqrt{X} = X
Here u have used \sqrt{x} = Mod(X) while in the problem below:
If \sqrt{3-2x}= \sqrt{2x} +1 then 4x2 =
(A) 1
(B) 4
(C) 2 − 2x
(D) 4x − 2
(E) 6x − 1
you have used \sqrt{X} = X
Why so?
\sqrt{x^2}=|x|.
If x\leq{0}. then \sqrt{x^2}=|x|=-x. For example if x=-5, then \sqrt{(-5)^2}=\sqrt{25}=5=|x|=-x.
If x\geq{0}, then \sqrt{x^2}=|x|=x. For example if x=5, then \sqrt{5^2}=\sqrt{25}=5=|x|=x.
I guess you are talking about the following problem: if-root-3-2x-root-2x-1-then-4x-135539.html Where did I write that \sqrt{x^2}=x?
P.S. Please read this: rules-for-posting-please-read-this-before-posting-133935.html#p1096628 Press m button when formatting. Thank you.