satya2029 explained it perfectly.
A.............B.............C............D
Suppose AD=600 Kms. Divide AD in 3 equal parts. AB=BC=CD=200 Kms
Case 1 - He travels distance AB by a train, distance BC by a train and distance CD by a car
Case 2- He travels distance AB by a train, distance BC by a car and distance CD bya car.
We can clearly see that he gonna take equal time to travel Distance AB and Distance CD in both cases, as he's using the same mean. So definitely gonna take extra time in case 2 while travelling Distance BC.
Hence, \(\frac{BC}{c} - \frac{BC}{t} = 0.5\) or \(\frac{200}{c} - \frac{200}{t} =0.5\)
Could you please explain how equation 1 is derived
A.............B.............C............D
Suppose AD=600 Kms. Divide AD in 3 equal parts. AB=BC=CD=200 Kms
Case 1 - He travels distance AB by a train, distance BC by a train and distance CD by a car
Case 2- He travels distance AB by a train, distance BC by a car and distance CD bya car.
We can clearly see that he gonna take equal time to travel Distance AB and Distance CD in both cases, as he's using the same mean. So definitely gonna take extra time in case 2 while travelling Distance BC.
Hence, \(\frac{BC}{c} - \frac{BC}{t} = 0.5\) or \(\frac{200}{c} - \frac{200}{t} =0.5\)
sume3tss wrote:
nick1816 wrote:
\(\frac{200}{c} - \frac{200}{t} = 0.5\) .....(1)
\(\frac{400}{t}+\frac{200}{c }= 6.5 \).....(2)
Subtract (1) from (2)
\(\frac{600}{t}= 6\)
t = 100
E
\(\frac{400}{t}+\frac{200}{c }= 6.5 \).....(2)
Subtract (1) from (2)
\(\frac{600}{t}= 6\)
t = 100
E
Manasvi1 wrote:
A man travels 600 km partly by train and partly by car. If he covers 400 km by train and the rest by car, it takes him 6 hours and 30 minutes. But if he travels 200 km by train and the rest by car, he takes half an hour longer. Find the speed of the train (T) and that of the car (C) in km/h .
A) T = 120, C = 100
B) T = 200, C = 180
C) T = 60, C = 50
D) T = 80, C = 60
E) T = 100, C = 80
A) T = 120, C = 100
B) T = 200, C = 180
C) T = 60, C = 50
D) T = 80, C = 60
E) T = 100, C = 80
Could you please explain how equation 1 is derived
