Re: What is the probability of getting at least one 11 in 3

The question is correct
It should be understood as follows
The possible combinations for sum of 11 is
TRIES first throw second throw third throw
1st 5 5 1
2nd 4 4 3
3rd 3 3 5
4th 3 6 2
5th 5 4 2
6th 6 4 1

Now it possible that in the first try the order may not be 5 5 1
It can also be 5 1 5 and so on
I mean to say that now we should also permute at each level

first throw second throw third throw
1st 5 5 1 3!/2! as two 5's are repeating=3*(3*1/6)

OR
2nd 4 4 3 " 4's " =3

OR
3rd 3 3 5 " 3's " =3

OR
4th 3 6 2 3! as none are repeating =6

OR
5th 5 4 2 " =6

OR
6th 6 4 1 " =6

Using addition theorem we get sum is 27

Probability= 27/216