ggarr wrote:
A cyclist rides his bicycle over a route which is 1/3 uphill, 1/3 level, and 1/3 downhill. If he covers the uphill part of the route at the rate of 16 miles per hour and the level part at the rate of 24 miles per hour, what rate in miles per hour would he have to travel the downhill part of the route in order to average 24 miles per hour for the entire route?
(A) 32
(B) 36
(C) 40
(D) 44
(E) 48
Please solve and explain why this doesn't this work:
1/3(16) + 1/3(24) + 1/3(x) = 24
And don't just give me your solution. Please let me know what's wrong w/the above. This equation was the first thing that came to my mind. I need to understand what I'm missing.
Please Show ALL work
(A) 32
(B) 36
(C) 40
(D) 44
(E) 48
Please solve and explain why this doesn't this work:
1/3(16) + 1/3(24) + 1/3(x) = 24
And don't just give me your solution. Please let me know what's wrong w/the above. This equation was the first thing that came to my mind. I need to understand what I'm missing.
Please Show ALL work
Let, each of three equal part of distance = 48 (LCM of 16 and 24)
24 = (total distance)/(total time)
or, 24 = 3 48 / (3+2+t)
or, t = 1 hour (for downhill part, time=t)
so, 48 miles/1 hours = 48m/h have to travel.