mahendru1992 wrote:
Let A's speed be 20 and B's speed be 13 and let the total distance be 100
=> Since B beats A by 20% of the length of the track, A only ran 80m.
=> So using the formula Rate*Time=Distance, A's Time= 4s
similarly B's Time= \frac{100}{13}
the difference between the Time of A and B is the time for which A has let B run ahead of him, i.e this is the headstart time
=> \frac{100}{13}-4 = \frac{48}{13}s
To get the distance simply multiply rate*time in case of B, which comes out to be 13*\frac{48}{13} = 48
Thus the answer 48%
=> Since B beats A by 20% of the length of the track, A only ran 80m.
=> So using the formula Rate*Time=Distance, A's Time= 4s
similarly B's Time= \frac{100}{13}
the difference between the Time of A and B is the time for which A has let B run ahead of him, i.e this is the headstart time
=> \frac{100}{13}-4 = \frac{48}{13}s
To get the distance simply multiply rate*time in case of B, which comes out to be 13*\frac{48}{13} = 48
Thus the answer 48%
will B travel 100 unit ????