blueseas wrote:
Asifpirlo wrote:
The equation of the curve shown in the figure is given by af(x) = ax^2 + bx - 3b . If (1,t) is a point on the curve, then in which quadrant does the point lie ?
(1) (2,3) is a point on the curve
(2) (3,9) is a point on the curve.
(1) (2,3) is a point on the curve
(2) (3,9) is a point on the curve.
[Reveal] Spoiler:
i have my explanation. please share your opinion. i will provide the solution soon ![:)]( "Smile")
since (1,t) lies on graph therefore this point will satisfy the equation af(x) = ax^2 + bx - 3b
therefore a*t = a - 2b ==.>2b = a(1-t).....(1
(1) (2,3) is a point on the curve
therefore ==> 3a = 4a - b==> b=a ==>puting a= b in 1
we can calculate t = -1
sufficient.
(2) (3,9) is a point on the curve.
therefore ==>9a = 9a +3b-3b==> insufficient.
hence A
Nice explanation...........