Rebecca runs at a constant rate on the treadmill and it takes her 2 hours longer to reach a certain milestone than the time it takes Jeff to reach that same milestone. If Jeff also moves at a constant rate and the two are allowed to combine their distances traveled to reach 25% beyond the initial milestone in 3 hours, how many hours would it take for Rebecca alone to reach the equivalent distance of 2 milestones?
Milestone = d
Rebecca = t+2
Jeff = t
1.25 = r*3
Rebecca: d=r*(t+2)
Jeff: d = r*(t)
r*t=1.25d
d/t+2 + d/t = 1.25d
(A) 4
(B) 6
(C) 8
(D) 10
(E) 12
Milestone = d
Rebecca = t+2
Jeff = t
1.25 = r*3
Rebecca: d=r*(t+2)
Jeff: d = r*(t)
r*t=1.25d
d/t+2 + d/t = 1.25d
(A) 4
(B) 6
(C) 8
(D) 10
(E) 12