study wrote:
can someone explain how to solve this problem the direct way.
I did the following, but didnt get to the right answer. What is wrong in my method?
6/8 * 5/7 = 30/56 = 15/28
The problem below is similar. And the answer is 8/10. So why cant the answer to the above be 6/8*5/7 ?
10 applicants are interviewed for a position. Among them are Paul and Jen. If a randomly chosen applicant is invited to interview first, what is the probability to have neither Paul nor Jen at the first interview?
* \frac{1}{10}
* \frac{1}{9}
* \frac{1}{2}
* \frac{8}{10}
* \frac{9}{10}
I did the following, but didnt get to the right answer. What is wrong in my method?
6/8 * 5/7 = 30/56 = 15/28
The problem below is similar. And the answer is 8/10. So why cant the answer to the above be 6/8*5/7 ?
10 applicants are interviewed for a position. Among them are Paul and Jen. If a randomly chosen applicant is invited to interview first, what is the probability to have neither Paul nor Jen at the first interview?
* \frac{1}{10}
* \frac{1}{9}
* \frac{1}{2}
* \frac{8}{10}
* \frac{9}{10}
Neither P nor J is different from atleast both p and J. In this case remember p can be selected or j can be selected but both p and j cant be selected. If you have to take the long route find the probability of getting 0 tulips that will be 6C2/8C2 15/28 and add it to the probability of 1 tulip and 1 other flower to be selected (2C1x6C1)/8C2 which will give you 12/28. Sum is 27/28.
Cheers
Posted from my mobile device
