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Re: ax + by=10, ay + bx=12. which one is greater here, x or y ?

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hb wrote:

Can you please explain a little bit more about the statement 2. How did you arrive at (a-b) ? I solved it as follows:
\frac{a}{b} >1
Multiply both sides by b.
a>b
This is the same as Statement 1. Hence the answer is D. Please clarify the answer.


highlited portion is wrong a/b>1
as you are multiplying both sides with b
there will be 2 cases
case 1: b>0
if b is +ve then equality sign doesnt change and hence you can come to a>b
case 2: b<0
if b is -ve then equality sign changes reslting equation will become a<b

now since we are not aware whether b is positive or negative so it is advisable not to multiply with b rather bring all thing on one side
therefore \frac{a}{b}-1>0
solving this \frac{(a-b)}{b}>0
now if b is-ve then a-b needs to be -ve hence a-b<0==> a<b
if b is +ve then a-b needs to be +ve hence a-b>0==> a>b

hope this helps

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