Rubina11 wrote:
The number (2^48 1) is exactly divisible by two numbers between 60 and 70. These numbers are
(A) 61, 63
(B) 61, 65
(C) 63, 65
(D) 63, 67
(E) 67, 69
(A) 61, 63
(B) 61, 65
(C) 63, 65
(D) 63, 67
(E) 67, 69
can be broken down to (2^24+1)(2^12+)(2^6+1)(2^6-1)
2^6+1= 65
2^6-1= 63