Lets just consider the left hand side of the inequality:
(x-y)/(x+y),
1) y < 0 , the left hand side of the numerator can now be rewritten as : (x+ |y|) / (x-|y|).
We can still not say that the numerator is larger than the denominator as we still do not know the value of x
e.g. , if x=-4 , y = -1
then , (x-y)/(x+y) = -3/-4 = 3/4 (<1)
if x =4 , y = -1
then , (x-y)/(x+y) = 5/3 (>1)
So this is insufficient
2) x+y > 0
=> x > -y
this is insufficient too
but if consider 1 and 2 together
from the second statement we have , x > -y ans since y < 0
x > |y|
So both statements are needed to prove the inequality
(x-y)/(x+y),
1) y < 0 , the left hand side of the numerator can now be rewritten as : (x+ |y|) / (x-|y|).
We can still not say that the numerator is larger than the denominator as we still do not know the value of x
e.g. , if x=-4 , y = -1
then , (x-y)/(x+y) = -3/-4 = 3/4 (<1)
if x =4 , y = -1
then , (x-y)/(x+y) = 5/3 (>1)
So this is insufficient
2) x+y > 0
=> x > -y
this is insufficient too
but if consider 1 and 2 together
from the second statement we have , x > -y ans since y < 0
x > |y|
So both statements are needed to prove the inequality