yezz wrote:
Is |x| < 1?
(1) |x + 1| = 2|x - 1|
(2) |x - 3| ≠ 0
(1) |x + 1| = 2|x - 1|
(2) |x - 3| ≠ 0
Questions asks if -1<x<1
From St1 we can say that since both LHS and RHS is positive therefore squaring both sides we get
(x+1)^2= 4(x-1)^2
On simplifying we get 3x^2-10x-3= 0 -----> x=3 or x= 1/3
2 ans and hence st 1 is not sufficient. Therefore Option A and D ruled out
St 2 we have |x - 3| ≠ 0 and since Modulus of any no is greater than or equal to 0 (In this case greater than 0) which means x not equal to 3
Not sufficient.
Combining both equation we see that x=1/3 which is in the Question stem range
Ans C
