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A circle with center (0, 0) and radius 8 will pass through all of the

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Bunuel wrote:
A circle with center (0, 0) and radius 8 will pass through all of the following points EXCEPT

A. (8, 0)
B. (0, 8)
C. (0, 8)
D. (8, 0)
E. (8, 8)


CONCEPT:

If Distance between the center of the circle and Point > the radius then the point lies outside the circle

If Distance between the center of the circle and Point < the radius then the point lies inside the circle

If Distance between the center of the circle and Point = the radius then the point lies on circumference of the circle



A. (8, 0) Distance of the point from center of the circle i.e. (0, 0) = 8 i.e. Point is on the circle
B. (0, 8) Distance of the point from center of the circle i.e. (0, 0) = 8 i.e. Point is on the circle
C. (0, 8) Distance of the point from center of the circle i.e. (0, 0) = 8 i.e. Point is on the circle
D. (8, 0) Distance of the point from center of the circle i.e. (0, 0) = 8 i.e. Point is on the circle
E. (8, 8) Distance of the point from center of the circle i.e. (0, 0) = \(82\) > RADIUS i.e. Point is outside the circle

Answer: Option E

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