Is 1 > |x-1| ?
Is |x-1|<1? --> Is -1<x-1<1? --> add 1 to each side: is 0<x<2?
(1) (x-1)^2 > 1 --> since both sides are non-negative, then we can safely take the square root: |x-1|>1. So, this statement directly gives a NO answer to the question. Sufficient.
(2) 0 > x. Sufficient.
Answer: D.
Hope it's clear.
Is |x-1|<1? --> Is -1<x-1<1? --> add 1 to each side: is 0<x<2?
(1) (x-1)^2 > 1 --> since both sides are non-negative, then we can safely take the square root: |x-1|>1. So, this statement directly gives a NO answer to the question. Sufficient.
(2) 0 > x. Sufficient.
Answer: D.
Hope it's clear.