Bunuel wrote:
A box contains 6 black balls and 4 white balls. If two balls are selected at random without replacement, what is the probability that both balls are white?
A. 7/90
B. 3/25
C. 2/15
D. 4/25
E. 4/9
A. 7/90
B. 3/25
C. 2/15
D. 4/25
E. 4/9
There are 10 balls in the box. The probability that the first ball drawn will be white is 4/10, and the probability that the second ball will also be white is 3/9. Thus, the probability of selecting two white balls, without replacement, is 4/10 x 3/9 = 2/5 x 1/3 = 2/15.
Answer: C