BankerRUS wrote:
pqhai wrote:
BankerRUS wrote:
For the first statement:
isn't n^5*(1-n^4) the same as n^5/n^5n^4??
In this case would A be sufficient. What am I missing?
isn't n^5*(1-n^4) the same as n^5/n^5n^4??
In this case would A be sufficient. What am I missing?
Hi BankerRUS
You mean n^5*(1-n^4) the same as
(1) [n^5/n^5n]^4
--OR--
(2) n^5/[(n^5n)^4].
Both of them are incorrect.
First, n^5*(1-n^4) = n^5 - n^9
But:
(1) [n^5/n^5n]^4 = n^20/n^20n
(2) n^5/[(n^5n)^4] = n^5/n^20n
So (1) and (2) differ from n^5 - n^9
Hope it's clear.
I think the question here is whether (1-n^4) is in the exponent or not...this is the misunderstanding I suppose.....if it in the exponent then your statement is not true..correct?
The question says: n^5*(1-n^4) ==> (1 - n^4) cannot be in the exponent.
If (1 - n^4) is in the exponent ==> the question will be n^[5*(1-n^4)]
Hope it helps.