WholeLottaLove wrote:
So,
This equation will always yield a value between -6 and 6 for any value of x.
Any value of x (positive or negative) will result in
(x+3) - (x-3)
But then how does that = 2x?
This equation will always yield a value between -6 and 6 for any value of x.
Any value of x (positive or negative) will result in
(x+3) - (x-3)
But then how does that = 2x?
The original function is p= |x+3|-|x-3|.
For values of x>3 it will equal 6
p=x+3-x+3=6
For values of x<3 it will equal -6
p=-x-3+x-3=-6
For values -6\leq{x}\leq{6} it equals p = (x+3)+(x-3)=2x, any value of x between -6\leq{x}\leq{6} will result in p=2x.
Some posts back we enstablished that
"Yes, almost correct! Remeber that we are considering the range -3<x<3 so the list of values is
-5/2 (-2.5), -2,-3/2,-1,-1/2,0,1/2,1,3/2,2,5/2 => 11 values
I said "almost correct" because in "x...i.e. 2, -2.....-1/2, 1/2" you missed -2.5 at the beginning, but everything else is fine "
what I am trying to say is that p=2x is a line, so I am asking you: "How many integer values does the function p=2x assume in the interval -6,6?"
Answer: if X=-5/2 P=-5, if X=-2 P= -4,...
Plus 6 and -6 that are the "edge" values: total 13.