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Re: Is |x-1| < 1?

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WholeLottaLove wrote:
Can someone explain to me how you arrive at 0<x≤2? I simplified (x-1)^2≤1 down to x(x-2)≤0 and I see that x≤2 but how do you get x<0?

Also, for #1, why couldn't x be one in addition to 0 and 2?

Thanks!


x(x-2)\leq{0} holds true for 0\leq{x}\leq{2}.tips-and-tricks-inequalities-150873.html

x can have any value in the interval [0-2], incluse 1

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