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Re: How many values can the integer p=|x+3|-|x-3| assume?

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Zarrolou wrote:
How many values can the integer p=|x+3|-|x-3| assume?
A)0
B)7
C)13
D)14
E)Cannot be determined

My own question, as always any feedback is appreciated

Dear Zarrolou,
Here's some feedback. I like the question itself quite a bit. My only criticism are the answer choices. Obviously, the OA (C) need to be on the list, and (B) 7 is an excellent distractor (what folks get if they just plug in integer values of x). I don't know about (D) 14 --- who would pick that? If folks realize that the output is +6 for x > 3 and -6 for x < -3, I could see them saying, "Hmm, how many integers from -6 to 6? That must be 12." Forgetting inclusive counting in something like this --- that's a huge predictable error. I think both 6 & 12 would be good to have on the answer list for this reason. I have no idea how anyone could possibly pick (A) 0 ---- anyone who can plug in any single number and get an output will know there are now zero outputs. I see that as a wasted incorrect answer: one that no one will pick. Choice (E) is debatable. I would recommend 3, 6, 7, 12, 13 as the answer choices myself.
What do you think?
Mike :-)

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