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Re: Is |x-1| < 1?

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WholeLottaLove wrote:
Can someone explain to me how you arrive at 0<x≤2? I simplified (x-1)^2≤1 down to x(x-2)≤0 and I see that x≤2 but how do you get x<0?

Also, for #1, why couldn't x be one in addition to 0 and 2?

Thanks!


What you have is x(x-2)≤0--> Thus, the two factors x and (x-2) are of opposite signs-->

Either x>0 AND x<2 --> 0<x<2
OR
x<0 AND x>2--> Invalid Solution.

Thus, taking the equality in consideration, we have 0≤x≤2.

x can be ANY value between 0 and 2, inclusive.

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