Quantcast
Channel: GMAT Club Forum - latest posts
Viewing all articles
Browse latest Browse all 420581

Re: A right circular cone is inscribed in a hemisphere so that

$
0
0
I know there are solutions to this question posted, however I have a follow-up clarifying question.

A right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere. What is the ratio of the height of the cone to the radius of the hemisphere?

Answer is 1:1

My question is, if you have a cone with a radius of 5 and a height of 1, how could the ratio be 1:1? You could have a very wide and short hemisphere. Am I missing something with regards to the cone being designated as a "right circular cone"? Can someone please explain?

Viewing all articles
Browse latest Browse all 420581

Trending Articles



<script src="https://jsc.adskeeper.com/r/s/rssing.com.1596347.js" async> </script>