10 A = 5 B =Cx= k = since work remain same that each does
10A = since work remains the same
10 A = A*2 + (A+B)2 + (A+B+C) *1/4
=> K = K/10 *2 + (K/10+K/5)2 + (K/10 + K/5 +k/x) *1/4
solving for above equation
=> 1/2 = 1/x
x =2 hours for C
10A = since work remains the same
10 A = A*2 + (A+B)2 + (A+B+C) *1/4
=> K = K/10 *2 + (K/10+K/5)2 + (K/10 + K/5 +k/x) *1/4
solving for above equation
=> 1/2 = 1/x
x =2 hours for C