x^2-x >|y|
x(1-x)>0 since RHS is always > 0
1>X>0
Statement 2 seems sufficient but I am unable to use statement 1 to conclude this logic
x(1-x)>0 since RHS is always > 0
1>X>0
Statement 2 seems sufficient but I am unable to use statement 1 to conclude this logic